Solve the equation of the two

Straightforward solving γf⩵γb this is not possible with Mathematica.
      Instead we solve [Graphics:../Images/impdist_gr_16.gif] which introduces negative solution as well, which we drop after solving

[Graphics:../Images/impdist_gr_17.gif]
[Graphics:../Images/impdist_gr_18.gif]
[Graphics:../Images/impdist_gr_19.gif]
[Graphics:../Images/impdist_gr_20.gif]

Therefore the minimal error γ is

[Graphics:../Images/impdist_gr_21.gif]
[Graphics:../Images/impdist_gr_22.gif]

Help a little in the simplification

[Graphics:../Images/impdist_gr_23.gif]
[Graphics:../Images/impdist_gr_24.gif]
[Graphics:../Images/impdist_gr_25.gif]
[Graphics:../Images/impdist_gr_26.gif]

Thus, γ is the minimum error achievable with imposter at optimal distance,
when viewed at distance r and angle θ

[Graphics:../Images/impdist_gr_27.gif]
[Graphics:../Images/impdist_gr_28.gif]
[Graphics:../Images/impdist_gr_29.gif]
[Graphics:../Images/impdist_gr_30.gif]


Converted by Mathematica      February 7, 2002